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{
mi=Mi(P,J);
p=P/1000000;
j=J;
}
mi=Mi(P,J);
}
printf("P=%5.2f\tJ=%5.2f\tMi=%5.4f\tHouDu=%10.8f\n",
p,j,mi,1.2*p*1000000*D/(2.3*YingLi+p*1000000));
for(P=5000000;P<=20000000;P+=100000)
{
j=J=0.5;
p=P/1000000;
printf("P=%5.2f\tJ=%5.2f\tMi=%5.4f\tHouDu=%10.8f\n",
p,j,mi=Mi(P,J),1.2*P*D/(2.3*YingLi+P));
}
P=20000000;
HouDu=1.2*P*D/(2.3*YingLi+P);
printf("HouDu=%10.8f\n",HouDu);
printf("%f %f\n",Mp,Mc);
scanf("*");
return 0;
}